b=45b^2

Solution for b=45b^2 equation:

b=45b^2

We move all terms to the left:

b-(45b^2)=0

determiningTheFunctionDomain
-45b^2+b=0

a = -45; b = 1; c = 0;
Δ = b2-4ac
Δ = 12-4·(-45)·0
Δ = 1
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1}=1$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-1}{2*-45}=\frac{-2}{-90}
=1/45
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+1}{2*-45}=\frac{0}{-90}
=0
$